#include
     
      #include
      
       #include
       
        using namespace std;int main(){    int N;    cin>>N;    while(N--)    {        double numC=0,numH=0,numN=0,numO=0;        string s;        cin>>s;        int len = s.length();        for(int i=0;i
        
         ='1'&&s[i]<='9'){                int tmp,flag=0;                    if(s[i+1]>='1'&&s[i+1]<='9'){                     tmp = (s[i]-'0')*10+s[i+1]-'0'-1;                     flag=1;                    }                     else                     tmp=s[i]-'0'-1;            if(s[i-1]=='C')numC+=tmp;            if(s[i-1]=='H')numH+=tmp;            if(s[i-1]=='O')numO+=tmp;            if(s[i-1]=='N')numN+=tmp;            if(flag==1)i++;            }        }        double sum = numC*12.01+numH*1.008+numN*14.01+numO*16.00;        cout<
         
          <
          
           <
           
            <
           
          
         
        
       
      
     

这个题目我能想到的就是这些啦，思路还是挺简单的，写的程序可能有点繁琐。